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2009
FEBRUARY

Eurotherm Plastic Solutions:

New Innovative and Application Specific Total Control Solutions for the Global Plastics Market

Find out how you can improve productivity and process functionality  Visit us at Plastindia2009.

February 4-9, New Delhi, India.

http://www.plastindia.org/

 

2008
OCTOBER

21-22 October, Nashville, TN.
Booth # 109-110

Visit us there or contact us about our new solutions for

  • Aerospace and Automotive audited processes:  AMS2750D, AS7102, SAT, TUS
  • Vacuum furnaces; vacuum sequence control with T2550 and Eycon
  • Gas Carburizing: NEW Solution delivers Quality Improvements. 
  • NEW 3G plus atmosphere controller
  • "Store and Forward" software
  • "Track and Trace" software

<click here for FNA2008 information>

MAY

NEW -  Lunch & Learn Seminars
Held on-site at your location.

Within a few hours find out how easy it is to implement machine control capabilities with a variety of offerings.

Find out how you can improve productivity and process functionality.


APRIL

17-20 April, 2008, Shanghai, CHINA

Plastic solutions offered at Chinaplas 2008

Booth E2 NO5  Hall E:2

Innovative, application specific, total control solutions for the global plastics market

EDITORS: visit the ONLINE press room for ChinaPlas 2008

 

MARCH

27-30 March, 2008

19th Korea International Plastics. Rubber Show, Koplas 2008

Innovative, application specific, total control solutions for the global plastics market 

<Eurotherm and the plastics industry>

FEBRUARY
NEW e Newsletter for the plastics processing industry: PLASTICS ... in the loop
 
 
Archive of Previous Years

What's New 2007
What's New 2006
What's New 2005
What's New 2004
What's New 2003
What's New 2002
What's New 2001
What's New 2000
What's New 1999
What's New 1998
What's New 1997
What's New 1996
What's New 1995



 
ANSWER to the PUZZLER: (ISSUE 11)
 
Three boards must be added.
Since the area of the table (A = π × r²) is 1,256 square inches, solve for r² by dividing 1,256 by 3.14. 1,256 square inches ÷ 3.14 = 400 square inches

Then find the radius by finding the square root of 400.
r = square root of 400 = 20 inches

So, 20 inches is half the diameter of the table, or half the length of each board. Each board is 40 inches long.

To find the total area of the additional boards, subtract the original area of the circular table from the increased area.
2,696 square inches − 1,256 square inches = 1,440 square inches

Find the area of each board by using the formula A = l × w.
A = 40 × 12 = 480 square inches

Divide the total area provided by the additional boards (1440) by the area of each board to get the final answer. 1,440 square inches ÷ 480 square inches = 3 boards

 

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Last Updated Thursday, July 31, 2008

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